X^2+50x+37=0

Solution for X^2+50x+37=0 equation:

X^2+50X+37=0

a = 1; b = 50; c = +37;
Δ = b2-4ac
Δ = 502-4·1·37
Δ = 2352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2352}=\sqrt{784*3}=\sqrt{784}*\sqrt{3}=28\sqrt{3}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-28\sqrt{3}}{2*1}=\frac{-50-28\sqrt{3}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+28\sqrt{3}}{2*1}=\frac{-50+28\sqrt{3}}{2}
$